Tuesday, April 5, 2011

Completed Solution - #3 Ksp Packet

Below is the finished solution to #3 from the Ksp packet. We started #3 in class, but ran out of time. The "Q" was larger than the Ksp value given, so a precipitate will form when the two solutions are placed together. Because a precipitate will form, the B.C.E. table will be used. Notice in the B.C.E. table, the two to one ratio of fluoride ion to barium ion is taken into account by dividing the 1.100 moles of fluoride ion (the limiting reactant) by two. This is also repeated for the formation of the precipitate barium fluoride. When solving for "x" in the Ksp problem, adding "x" to the barium initial concentration was not taken into account because the disparity between the Ksp value and initial concentration of barium ion was large. The percentage between the two was 0.4%. Notice how a confirmation was done at the end of the problem to ensure that the problem was done correctly. A podcast was made showing the solution to #4 of the Ksp packet. The solution can be found on the Events Calendar of the class website under the date April 4th.. Please finish #5 for tomorrow.

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